Jul 21EditedMindaugas Šarpis@mindaugasΛb0→Λc+Dˉ∗0K−\Lambda_b^0 \rightarrow \Lambda_c^+ \bar{D}^{*0} K^{-}Λb0→Λc+Dˉ∗0K− Anyone?Like1Cite2Comment2SaveLinkSign in to comment